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Anna11 [10]
1 year ago
5

For f(x)=4x+1 and g(x) = x^2 - 5, find (f+g)(x).

Mathematics
1 answer:
Rus_ich [418]1 year ago
3 0

Answer:

(f + g)(x) = x² + 4x - 4  

Step-by-step explanation:

The statement (f + g)(x) is the same as f(x) + g(x). In other words, the question simply wants you to add the two functions together.

f(x) = 4x + 1

g(x) = x² - 5

(f + g)(x)                                  <----- Original statement

f(x) + g(x)                                <----- Rewrite

(4x + 1) + (x² - 5)                     <----- Substitute the equations in f(x) and g(x)

4x + x² - 4                              <----- Add 1 and -5

x² + 4x - 4                              <----- Rearrange the terms

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{ \qquad\qquad\huge\underline{{\sf Answer}}}

We need to find thr rate of change (slope) of the line joining these two points ~

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\qquad \sf  \dashrightarrow \: m =  \cfrac{8  +  8}{0  + 8}

\qquad \sf  \dashrightarrow \: m =  \cfrac{16}{8}

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Slope of the line (m) joining the two points is 2 ~

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2 years ago
All of the following expressions have the same value, except . . .
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Answer: -3/7- 4/7

Step-by-step explanation:

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3 years ago
What is the area of this trapezoid?
pantera1 [17]

Answer:

Area=80 units squared

A=base*height

A=base*height/2

Step-by-step explanation:

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3 years ago
Read 2 more answers
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

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Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

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Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

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2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

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3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

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Find the simple interest earned on $750 at 6% for 18 months
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Answer:

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Step-by-step explanation:

You said earned 750 %6 x 18 montjs

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