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Rus_ich [418]
3 years ago
6

What two numbers added will give you 7 but multiplied give you -18

Mathematics
2 answers:
Sedbober [7]3 years ago
4 0

Answer:

9 and -2

Step-by-step explanation:

9 - 2 = 7

9 * -2 = -18

Bond [772]3 years ago
3 0

-2 and 9

hope this helps!!!

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Do I do KFC on this question? If not what do I do??
nataly862011 [7]

Answer:

uh its KCF not KFC, and yes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A stadium can seat 16,000 people at full capacity. If there are 13,920 people in the stadium, what percentage of the capacity is
katrin [286]

Answer:

87%

Step-by-step explanation:

In order to get 87% you divide 16000 by 13920

16000/13920= 0.87

To convert this into a percentage you can multiply by 100

0.87 * 100 =87

Answer: 87%

I hope this helps :)

4 0
3 years ago
Read 2 more answers
|6/-a - 2| = 25
Nat2105 [25]
So I am assuming we’re solving for a?
If so,
|(6/-a) - 2 | = 25

|(6/-a)| = 25 + 2

|(6/-a)| = 27
Multiply both sides of equation by -a and you get

6 = 27a
(6/27) = a
0.222 = a

So, we can check by plugging 0.222 in the original equation,

|(6/-0.222) - 2 |=25
|27-2|=25
25=25 which is correct
7 0
2 years ago
Please answer below :-)
katrin2010 [14]

Step-by-step explanation:

\frac{2x - 1}{4}  +  \frac{x}{3}  = 2

find a common denominator of 12 for each fraction

\frac{3}{3}  \times  \frac{(2x - 1)}{4}  +  \frac{4}{4}  \times  \frac{x}{3}  =  \frac{12}{12}  \times  \frac{2}{1}

\frac{6x - 3}{12}  +  \frac{4x}{12}  =  \frac{24}{12}

\frac{6x - 3 + 4x}{12}  =  \frac{24}{12}

\frac{10x - 3}{12}  =  \frac{24}{12}

multiply both sides by 12

12 \times  \frac{10x - 3}{12}  =  \frac{24}{12}  \times 12

12s cancel out

10x - 3 = 24

add three to both sides

10x - 3 + 3 = 24 + 3

10x = 27

divide both sides by 10

\frac{10x}{10}  =  \frac{27}{10}

The tens on the left side cancel

x =  \frac{27}{10}  = 2.7

4 0
3 years ago
Can someone please check this?
GrogVix [38]
I think there is a diagram given for the question above. Nevertheless, here is what I have based on my research.

<span>Given: Line segment AB is congruent to line segment AC, angle BAD is congruent to CAD
 Prove: line segment AD bisects line segment BC
</span>
<span>Statements:
1. line segment AB is congruent to line segment AC
2. angle BAD is congruent to angle CAD
3. line segment AD is congruent to line segment AD
4. Triangle BAD is congruent to triangle CAD
5. line segment BD is congruent to line segment CD
6. Line segment AD bisects line segment BC
 
Reasons:
1. Given
2. Given
3. Reflexive Property
4. SAS
5. </span><span>CPCTC Theorem</span><span>
6. Definition of Segment Bisector</span>

3 0
3 years ago
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