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vladimir2022 [97]
3 years ago
7

Can someone please check this?

Mathematics
1 answer:
GrogVix [38]3 years ago
3 0
I think there is a diagram given for the question above. Nevertheless, here is what I have based on my research.

<span>Given: Line segment AB is congruent to line segment AC, angle BAD is congruent to CAD
 Prove: line segment AD bisects line segment BC
</span>
<span>Statements:
1. line segment AB is congruent to line segment AC
2. angle BAD is congruent to angle CAD
3. line segment AD is congruent to line segment AD
4. Triangle BAD is congruent to triangle CAD
5. line segment BD is congruent to line segment CD
6. Line segment AD bisects line segment BC
 
Reasons:
1. Given
2. Given
3. Reflexive Property
4. SAS
5. </span><span>CPCTC Theorem</span><span>
6. Definition of Segment Bisector</span>

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Now consider the fraction

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For all k < 10, the fraction tex]\dfrac{3,240}{k}[/tex] is not a square number (this follows from factorization).

Or you can simply check the values of the fraction for all k < 10:

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  • k = 3, \dfrac{3,240}{3}=1,080 is not a square number;
  • k = 4, \dfrac{3,240}{4}=810 is not a square number;
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  • k = 7, \dfrac{3,240}{7} is not a square number;
  • k = 8, \dfrac{3,240}{8}=405 is not a square number;
  • k = 9, \dfrac{3,240}{9}=360 is not a square number.
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3 years ago
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