Question

A person invests $1,150 in an account that earns 5% annual interest compounded continuously. Find when the value of the investment reaches $2,000. If necessary round to the nearest tenth.
The investment will reach a value of $2,000 in approximately_____years.

Answer 1

Answer:

11.1 years

Step-by-step explanation:

The formula for interest compounding continuously is:

$A(t)=Pe^{rt}$

Where A(t) is the amount after the compounding, P is the initial deposit, r is the interest rate in decimal form, and t is the time in years.  Filling in what we have looks like this:

$2000=1150e^{{.05t}$

We will simplify this first a bit by dividing 2000 by 1150 to get

$1.739130435=e^{.05t}$

To get that t out the exponential position it is currently in we have to take the natural log of both sides.  Since a natural log has a base of e, taking the natual log of e cancels both of them out.  They "undo" each other, for lack of a better way to explain it.  That leaves us with

ln(1.739130435)=.05t

Taking the natural log of that decimal on our calculator gives us

.5533852383=.05t

Now divide both sides by .05 to get t = 11.06770477 which rounds to 11.1 years.