Consider the quadratic equation x3 = 48-5. How many solutions does the equation have?
2 answers:
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Answer:
(1,6)
x = 1, y = 6
See attachment for the graph
Step-by-step explanation:
y=x+5
y=-x+7
Using the elimination process
y=x+5
- y=-x+7
----------------
0=2x-2
2=2x
1=x
x=1
Substitute x = 1
y = x + 5
y = 1 + 5
y = 6
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