All categories

4 years ago

Did I get this right? Please help I’ll give brianlist

Mathematics

2 answers:

const2013 [10]4 years ago

8 0

Answer:yes

Step-by-step explanation:

fredd [130]4 years ago

4 0

Answer:

it should be something like 3.75/1 because she walks a distance of 3.75 over the span of 1 hour... So I think its 3.75, not 1/3.75.

You might be interested in

Kobe wants to organize his toys. His box has a width 2 2/3 feet, length 3 1/3 feet, and height 2 1/3 feet?

Tanya [424]

Answer:

Cubic feet = Length (3 1/3 feet) x Width (2 2/3 feet) x Height (2 1/3 feet)

Step-by-step explanation:

3 1/3 x 2 2/3 x 2 1/3 = approximately 20.74 cubic feet

3 0

3 years ago

Help me pls!!!!!!!!!

Dominik [7]

Answer:

$x^2+18=-9x : x = -3, x = -6$

Step-by-step explanation:

$x^2+18=-9x$

Add 9x to both sides:

$x^2+18+9x=-9x+9x$

Simplify:

$x^2+9x+18=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3$

$x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6$

The solution to the quadratic equation are:

$x=-3,\:x=-6$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0

3 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

6 0

3 years ago

2^x=3^x+1 what are the exact approximate solutions

Mashcka [7]

Answer:

Step-by-step explanation:

The goal of course is to solve for x. Right now there are 2 of them, one on each side of the equals sign, and they are both in exponential positions. We have to get them out of that position. The way we do that is by taking the natural log of both sides. The power rule then says we can move the exponents down in front.

$ln(2^x)=ln(3^{x+1})$ becomes, after following the power rule:

x ln(2) = (x + 1) ln(3). We will distribute on the right side to get

x ln(2) = x ln(3) + 1 ln(3). The goal is to solve for x, so we will get both of them on the same side:

x ln(2) - x ln(3) = ln(3). We can now factor out the common x on the left to get:

x(ln2 - ln3) = ln3. The rule that "undoes" that division is the quotient rule backwards. Before that was a subtraction problem it was a division, so we put it back that way and get:

$x(\frac{ln(2)}{ln(3)})=ln(3)$ . We can factor out the ln from the left to simplify a bit: