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jenyasd209 [6]
3 years ago
8

Correlation of a scatter plot question in image

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer: Strong negative

Step-by-step explanation:

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Rolling 7 or 11 on the first roll is a win probability of winning on 1st roll
gtnhenbr [62]

1/6 plus 1/18, which equals to 2/9. Suppose we roll 4 on the first roll (the probability of rolling 4 is 1/12). On each successive roll the probability of rolling 7 is 1/6 and the probability of rolling 4 is 1/12.

[i.dk how this can help but if you got a 7 or 11 rolling on the first round you would probably win]

5 0
3 years ago
Suppose the number of hits a webpage receives follows a Poisson distribution. The average number of hits per minute is 2.4.
JulijaS [17]

Answer: a) P(x=0) = 0.0907, b) P(x≥10) = 0.7986

Step-by-step explanation: the probability mass function of a possion probability distribution is given as

P(x=r) = (e^-λ)×(λ^r) /r!

Where λ = fixed rate at which the event is occurring and each event is independent of each other = 2.4

a) P(x= at least one) = P(x≥1)

P(x≥1) = 1 - P(x<1)

But P(x<1) = P(x=0) { we can not continue to negative values because our values of x can only take positive values of integer}

Hence, P(x≥1) = 1 - P(x=0)

P(x=0) = e^-2.4 * 2.4^0/(0!)

P(x=0) = 0.0907×1/1

P(x=0) = 0.0907

b) if the average number of hits in 1 minutes is 2.4 then for 5 minutes we have 2.4×5 = 12.

Hence λ = 12.

P(x= at least 10) =P(x≥10) = 1 - P(x≤9)

P(x≤9) will be gotten using a cumulative possion probability distribution table whose area is to the left of the distribution.

From the table P(x≤9) = 0.2014.

P(x≥10) = 1 - 0.20140

P(x≥10) = 0.7986

4 0
3 years ago
According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating
Natali [406]

Answer:

a) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

H_0: \mu=32.48\\\\H_a:\mu< 32.48

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565

The degrees of freedom for this sample size are:

df=n-1=65-1=64

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

<u>Critical value approach</u>

<u></u>

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0
3 years ago
What steps should be used to find 55% of 300? Check<br> all that apply.<br> ger
densk [106]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:d

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5 0
3 years ago
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