Answer:
Table a match with Graph 3
Table b match with Graph 2
Table c match with Graph 4
Step-by-step explanation:
<u>Table a</u>
Time is plotted on x - axis and Temp on y axis
From table a we can see that the y values(temp) decrease with increasing time. The only graph that has a decreasing trend is Graph 3
<u>Table b</u>
Time plotted on x axis, cost on y axis
Looking at the values we see that they are almost linear except for 2 values at x = 2 and 2.5 and at y = 5 and 5.3.
Ignoring values 2.5 and 5.3 we see a linear fit with a slope of 20. This means either graph 1 or graph 2
However, the graph passes through (0,0) and this is not a set of values in the table. That leaves graph 2
<u>Table c</u>
Months plotted on x axis and length of fetus on the y axis
We can see that the y values (the length) increases slowly at lower values of x(x=1 and x=2) and then increase rapidly at the mid values(x = 2 thru 6) and then slows down between months 6 and 9. Only Graph 4 fits this pattern
Answer/Step-by-step explanation:
Given:
m<3 = 54°
m<2 = right angle
a. m<1 + m<2 + m<3 = 180° (angles in a straight line)
m<1 + 90° + 54° = 180° (substitution)
m<1 + 144° = 180°
m<1 = 180° - 144°
m<1 = 36°
b. m<2 = 90° (right angle)
c. m<4 = m<1 (vertical angles)
m<4 = 36° (substitution)
d. m<5 = m<2 (vertical angles)
m<5 = 90°
e. m<6 = m<3 (vertical angles)
m<6 = 54°
f. m<7 + m<6 = 180° (same side interior angles)
m<7 + 54° = 180° (substitution)
m<7 = 180 - 54
m<7 = 126°
g. m<8 = m<6 (alternate interior angles are congruent)
m<8 = 54°
h. m<9 = m<7 (vertical angles)
m<9 = 126°
i. m<10 = m<8 (vertical angles)
m<10 = 54°
j. m<11 = m<4 (alternate interior angles are congruent)
m<11 = 36° (substitution)
k. m<12 + m<11 = 180° (linear pair)
m<12 + 36° = 180° (substitution)
m<12 = 180° - 36°
m<12 = 144°
l. m<13 = m<11 (vertical angles)
m<13 = 36°
m. m<14 = m<12 (vertical angles)
m<14 = 144° (substitution)
Answer:
x+4= -2+4
x+4 = 2
Step-by-step explanation:
