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Tcecarenko [31]
3 years ago
5

What is nine tenths in standard form? I know it's simple but I forgot.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0
That would be 0.9 because 9 is in the tenths place
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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
3 years ago
Find tan if sin theta= 1/4 and falls in Quadrant 2.
7nadin3 [17]
If sinα=1/4 and it is in q2 it means that the x coordinate is negative.

The triangle has a height of one and a hypotenuse of 4 so:

x=-√(4^2-1)

x=-√15

so tanα=-1/√15

tanα=-√(1/15)

tanα≈ -0.258


6 0
3 years ago
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Complete function tables part 2<br><br><br>please help i will mark as brainlyst<br>​
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0

2

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6

1 = 1/2(0) + 1

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3 = 1/2(4) + 1

4 = 1/2(6) + 1

hope this helps!

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How do I solve the linear equation of 27=6(x)+4(y) over 20=2(x)+5(y)
larisa86 [58]
<u>27 = 6x + 4y </u>= 1 7/20 = 3 4/5<u>
</u>20 = 2x + 5y<u>
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3 years ago
PLEASE HELP ALGEBRA 2
svet-max [94.6K]


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2) All positives

3) Square root of 343

4) Square root of 48

I hope that helps. :)

4 0
4 years ago
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