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3 years ago

I need to understand this math.

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

Just think of for example 6x4=24 so the Division problom would be 24 divided by 4 or 6 the answer would be 6 or 4

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A room has an area of 216 square feet. One dimension is 6 feet more than the other. Find the length of the longer side.

zlopas [31]

The dimensions would be x and x+6. The area is 216.

x(x+6) = 216
x^2 + 6x - 216 = 0
(x-12)(x+18) = 0

x = 12---Yes---
x = -18---No, sides cannot be negative---

If one side is 12, the other side is 18. To check:

12 * 18 = 216
216 = 216

Correct

3 0

3 years ago

Read 2 more answers

In order to solve the equation -3x - 6 = 5, the first step is to:

7nadin3 [17]

Add 6 to both sides so that you can get the variable by itself

3 0

3 years ago

Read 2 more answers

Can someone explain the process of getting to Angle A? I know the answer is 44.1 but I need to show my work so can someone show

dsp73

Answer:

Step-by-step explanation:

First you have to calculate CB in order to use sin law to calculate ∠A

CB= $\sqrt{18.4^{2} -13.2^{2} }$

CB=12.8(correct to nearest tenth)

After that, use sin law to calculate ∠A,

$\frac{18.4}{sin90} =\frac{12.8}{sinA}$ or $\frac{sin90}{18.4} =\frac{sinA}{12.8}$

sinA=0.695...

A=44.079...

=44.1(corrext to the nearest tenth)

Is that clear enough for you?

4 0

3 years ago

a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure

dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

$y=-0.01x^2+0.5x+3$

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

$8=-0.01x^2+0.5x+3$

$8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100$

$800=-x^2+50x+300$

$-x^2+50x-500=0$

$x^2-50x+500=0$

we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}$

$x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)$

$x=13.82,x=36.2$

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

$y=-0.01(30)^2+0.5(30)+3$

$y=9ft$

we know that

height of net is 8 ft

so, the ball will go over the net

5 0

3 years ago

The 8th and 20th terms of an arithmetic sequence are 20 and 56 respectively. What is the 1st term of the sequence.

Ostrovityanka [42]

Answer:

Step-by-step explanation:

$a_n=a_1+d(n-1)\\\\a_8=a_1+d\cdot7\\\\a_{20}=a_1+d\cdot19\\\\a_{20}-a_8=a_1+19d-(a_1+7d)=12d\\\\56-20=2d\\\\12d=36\\\\d=3\\\\\\ a_1+3\cdot7=20\\\\a_1=20-21=-1$

6 0

3 years ago