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3 years ago

I need to understand this math.

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

Just think of for example 6x4=24 so the Division problom would be 24 divided by 4 or 6 the answer would be 6 or 4

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Sam intends to roll a six sided cube 100 times. What is the probability model he can use to predict whether or not each roll wil

bekas [8.4K]

The outcomes of rolling fair six sided die is $\{1,2,3,4,5,6\}$ . The prime numbers in the above outcomes are $\{2,3,5\}$ . The probability of not rolling a prime number is $p=\frac{3}{6}= 0.5$ .

Each trial is independent.

In the given experiment of 100 trials, the binomial probability model can be used to predict the number of occurrence of non-prime numbers (X). The probability mass function is

$P(X=x)=C(100,x)p^x(1-p)^{100-x},x=0,1,2,3,...,100$ . Since $p=0.5,1-p=0.5$

$P(X=x)=C(100,x)0.5^x(0.5)^{100-x},x=0,1,2,3,...,100 \\ P(X=x)=C(100,x)(0.5)^{100},x=0,1,2,3,...,100$

8 0

3 years ago

Read 2 more answers

Scatter plots & trend lines is there a easier way to do this?

ira [324]

Answer:

Step-by-step explanation:

Using the best fit equation y = 1.5x - 1

with x = 16 ( number of years since 2000 ), then

y = (1.5 × 16) - 1 = 24 - 1 = 23

7 0

3 years ago

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

3 years ago

Algebra 2<br><br> Solve each equation to the nearest thousand <br><br> Help pls

borishaifa [10]

I don’t understand your question, can you give more details please

5 0

3 years ago

Which relation represents a function?

Tom [10]

C is the rigth answer because all the other three has two x values in common. :)

8 0

3 years ago