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Lera25 [3.4K]
3 years ago
12

A bag contains 5 blue, 3 red, 6 green, 9 orange, and 20 black marbles. What is the ratio of the number of blue marbles to the nu

mber of marbles that are orange or green?​

Mathematics
2 answers:
Zigmanuir [339]3 years ago
5 0

Answer:the answer is C

Step-by-step explanation:there are 5 blue marbles then you add 6 green and 9 orange, that makes 15 so your answer is 5 to 15

barxatty [35]3 years ago
4 0

Answer:

C

Step-by-step explanation:

blue+green=15

blue is 5

5 to 15

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natita [175]

Answer:

24s^2, 54s^2, 96s^2

Step-by-step explanation:

Let s represent the initial side length of the cube.  Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).

a) Now suppose we double the side length.  The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),

b) tripled:  A = 6(3s)^2 = 54x^2

c) quadrupled?  A = 6(4s)^2 = 96s^2

6 0
3 years ago
The measure of two vertical angles are 6x - 22 and 4x + 2. Find x.
maks197457 [2]
Vertical angles are congruent...they are equal....so set them equal to each other and solve for x

6x - 22 = 4x + 2
6x - 4x = 2 + 22
2x = 24
x = 24/2
x = 12 <==



6 0
3 years ago
A right triangle has an area of 50 square inches. If the triangle is an isosceles triangle, what are the lengths of the legs of
Fed [463]
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length.  Orient the base of this triangle so that it's horizontal, and represent its length by b.  Let h represent the height of the triangle.  Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.   

Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2.  Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).

The length of one of the legs is the sqrt of  [5sqrt(2)]^2+[5sqrt(2)]^2, or

sqrt(25(2)+25(2)) = sqrt(100) = 10.



</span>
4 0
3 years ago
L is between M and N. If NL = 5x, LM = 3x, and NL = 15, find x.
Leona [35]

Answer:

x = 5

Step-by-step explanation:

Given that,

NL = 5x, LM = 3x, and NL = 15

L is between M and N.

To find,

The value of x.

Solution,

It is mentioned that, L is between M and N. So,

LM = LN

Put all the values,

3x = 15

⇒ x = 5

So, the value of x is equal to 5.

Reference,

brainly.com/question/19871240

6 0
2 years ago
Help me pleaseee.....
Lana71 [14]

Answer:

titutex=cos\alp,\alp∈[0:;π]

\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+

1−x

2

∣=

2

(2x

2

−1)\Leftright∣cos\alp+sin\alp∣=

2

(2cos

2

\alp−1)

\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N

2

cos(\alp−

4

π

)∣=N

2

cos(2\alp)\Right\alp∈[0;

4

π

]∪[

4

3π

;π]

1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;

4

π

]

\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−

4

π

)=cos(2\alp)…

2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[

4

3π

;π]

\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−

4

π

)=cos(2\alp)…

1

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6 0
3 years ago
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