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3 years ago

288 miles on 12 gallon of fuel 240 miles on 10 of foul. it's a equivalent ratio

Mathematics

1 answer:

Andrew [12]3 years ago

5 0

288+12=24

240÷10=24

the equivalent ratio would be 24:1. 24 miles for every gallon of fuel.

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Write the prime factorization of 6. Use exponents when appropriate and order the factors from least to greatest (for example, 2

attashe74 [19]

Answer:

The prime factorization of $6$ is $2\times 3$ .

Step-by-step explanation:

A prime number is a number that can be divided by 1 or by itself, whereas a composite number is a product of prime numbers. The number 6 is equal to the product of 2 and 3, which are prime numbers:

$2\times 3 = 6$

The prime factorization of $6$ is $2\times 3$ .

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Write the function , √(x^3+6)/√(x^3-9) as a composition of three or more non-identity functions.

tamaranim1 [39]

Answer:

$h \circ m \circ n \text{ where } h(x)=\sqrt{x} \text{ and } m(x)=1+\frac{15}{n} \text{ and } n(x)=x^3-9$

Step-by-step explanation:

Ok so I see a square root is on the whole thing.

I'm going to let the very outside function by $h(x)=sqrt(x)$ .

Now I'm can't just let the inside function by one function $g(x)=\frac{x^3+6}{x^3-9}$ because we need three functions.

So I'm going to play with $g(x)=\frac{x^3+6}{x^3-9}$ a little to simplify it.

You could do long division. I'm just going to rewrite the top as

$x^3+6=x^3-9+15$ .

$g(x)=\frac{x^3-9+15}{x^3-9}=1+\frac{15}{x^3-9}$ .

So I'm going to let the next inside function after h be $m(x)=1 + \frac{15}{x}$ .

Now my last function will be $n(x)=x^3-9$ .

So my order is h(m(n(x))).

Let's check it:

$h(m(x^3-9))$

$h(1+\frac{15}{x^3-9})$

$h(\frac{x^3-9+15}{x^3-9})$

$h(\frac{x^3+6}{x^3-9})$

$\sqrt{ \frac{x^3+6}{x^3-9}}$

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3 years ago

23.96448 to the nearest tenth

Ulleksa [173]

The answer is 24 this needs to be longer so it will send

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