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3 years ago

(3n^3)^2 without exponet

Mathematics

1 answer:

sergejj [24]3 years ago

4 0

Step-by-step explanation:

$(3 {n}^{3} )^{2} \\ = {3}^{2} \times {n}^{3 \times 2} \\ = 9{n}^{6}$

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Please help with this question it is due today I will give 20 points. Thank you and may God bless you! :)

Ronch [10]

I would say A but please wait for someone else to answer to make sure it's not wrong I would hate for you to get this wrong

6 0

3 years ago

5. Susan receives a Federal Direct Subsidized Loan for $1,000 as a freshman in

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

subsidized means that they pay for it

4 0

2 years ago

Are 2x+y=5 and y=-1/2x+1 parallel perpendicular or neither

choli [55]

Answer:

neither

Step-by-step explanation:

if the slopes were the same it wouldve been parallel, if the slopes were oppsite it wouldve been perpendicular but its neither

4 0

2 years ago

Bottom left Angle: <br><br> Top Angle:<br><br> Bottom right Angle:

Arturiano [62]

Angles in a triangle always add up to 180 degrees

Here, we add up all the angles given to equal it to 180 degrees:

X + X + 10 + X + 5 = 180

Collect like terms -> 3X + 10 + 5 = 180

Add the whole numbers -> 3X + 15 = 180

Take 15 from to the other side (then make it negative) to isolate the X:
3X = 180 - 15

The subtract -> 3X = 165

Take 3 over to the other side (and it it should divide 165) and isolate the X -> X = 165/3

Finally, X = 55

Now wherever you see X in the triangle, replace it with 55.

With that, the top angle = 55 + 10 = 65 degrees
The bottom left angle = 55 + 5 = 60 degrees
The bottom right angle = 55 degrees

8 0

3 years ago

SCALCET8 3.9.026.MI. A trough is 10 ft long and its ends have the shape of isosceles triangles that are 5 ft across at the top a

kherson [118]

Answer:

The answer is "0.624"

Step-by-step explanation:

$b = 5x\\\\h = x\\\\ l = 10 \\$

Using formula:

$V = (\frac{1}{2})(b)(h)(l) \\\\$

$= \frac{1}{2} \times (5x)\times (x) \times (10)\\\\= 5x\times x \times 5\\\\= 25x^2$

$\frac{dV}{dt} = 50x \ \frac{dx}{dt} \\\\\text{(where x represents the height in feet and}\ \frac{dv}{dt} = 13\ \frac{ft^3}{min})\\\\\frac{dx}{dt} = (\frac{1}{50})(\frac{1}{x}) \ \frac{dV}{dt}\\\\$

When the water is 5 inches deep then:

$x = (\frac{5}{12})\ ft\\\\13 =50(\frac{5}{12}) \ \frac{dx}{dt}\\\\13 \times 12 =50(5) \ \frac{dx}{dt}\\\\\frac{13 \times 12}{50 \times 5} = \frac{dx}{dt}\\\\\frac{156}{250} = \frac{dx}{dt}\\\\ \frac{dx}{dt}= 0.624$

5 0

3 years ago