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4 years ago

How do you write an equation off a coordinate plane graph?

1 answer:

8 0

There is a Y axis and a X axis on the graph, they can be our equation. If the plot is (1,3) then, X=1 and Y=3, you can assume that it's X = 3. If the plot is (2,4), then X = 2, Y = 4, just divide/ simplify both sides my 2, and X = 2.

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What divided by 6 equals 7

vivado [14]

Answer:

Step-by-step explanation:

You can prove this by taking 42 and dividing it by 6, and you will see that the answer is 7. Tip: For future reference, when you are presented with a problem like "What divided by 6 equals 7?", all you have to do is multiply the two known numbers together.

6 0

3 years ago

Read 2 more answers

Me. Silvera bought a can of paint. He used 3/8 of it to paint a fence and 1/4 to paint a table top. He painted a chair with some

LuckyWell [14K]

Well, seeing the information above, he used 5/8 of paint to paint the fence and table top. If he only had 1/8 left of the paint, he used 2/8 on the chair.

I found the 5/8 because I needed a common denominator. I multiplied the top and bottom by 2 to get 2/8. 3/8+2/8=5/8, and then I added 2/8 to the 5/8 that then gave me 7/8 of paint used, and 1/8 of paint left.

Hope I helped!

3 0

4 years ago

Graph triangle RST with vertices R3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over 3

Alja [10]

Skis dhdjaknsjdkjshdjdkbsjfkdnbskdksndjrjdbndje

6 0

3 years ago

1. A magazine advertise its $12 annual subscription price 70% off the newsstand price. What is the number of dollars per year a

ollegr [7]

1. $17.14

12 represents 70%
x represents 100%

rule of three

Price Percentage
+12 70-
-x 100+

$x= \frac{12*100}{70} 
 \\ \\
x= \frac{12*10}{7} 
 \\ \\ x=17.14$

3 0

3 years ago

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago