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lesya [120]
3 years ago
14

table Given the graph of a linear function, identify the steps used to find the initial value. Check all that apply. Find the ra

te of change using rise over run. Find corresponding y values when x = 6, x = 7, and x = 8. Then plot the points to finish the line. Find corresponding y values when x = 2, x = 1, and x = 0. Then plot the points to finish the line. The initial value corresponds to the y value when x = 1. The initial value corresponds to the y value when x = 0.
Mathematics
2 answers:
____ [38]3 years ago
6 0

Answer:

1,3,5

Step-by-step explanation:

just did the assignmanet question

Doss [256]3 years ago
5 0

Answer:

  • The initial value corresponds to the y value when x = 0

Step-by-step explanation:

Since the graph is given, it is unnecessary to "finish the line." It is only necessary to read the value of y from the graph where x=0.

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3 years ago
Four times the quotient of 3 and 4.
scoray [572]

Answer:

the answer would be 3.

Step-by-step explanation:

i hope this helps

3 0
3 years ago
QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Find the exact values of the six trigonometric functions for angle theta in standard positi
DIA [1.3K]

x = -6, y = 6, Now find the hypotenuse:

(-6)² + (6)² = hypotenuse²

36 + 36 = hypotenuse²

   2(36) = hypotenuse²

 √2(36) = hypotenuse

      6√2 = hypotenuse

sin\ \theta=\dfrac{y}{hypotenuse}=\dfrac{6}{6\sqrt2}=\dfrac{1}{\sqrt2}\cdot \dfrac{\sqrt2}{\sqrt2}=\boxed{\dfrac{\sqrt2}{2}}\\\\\\cos\ \theta=\dfrac{y}{hypotenuse}=\dfrac{-6}{6\sqrt2}=-\dfrac{1}{\sqrt2}\cdot \dfrac{\sqrt2}{\sqrt2}=\boxed{-\dfrac{\sqrt2}{2}}\\\\\\tan\ \theta=\dfrac{y}{x}=\dfrac{-6}{6}=\boxed{-1}\\\\\\csc\ \theta=\dfrac{hypotenuse}{y}=\dfrac{6\sqrt2}{6}=\boxed{\sqrt2}\\\\\\sec\ \theta=\dfrac{hypotenuse}{x}=\dfrac{6\sqrt2}{-6}=\boxed{-\sqrt2}

cot\ \theta=\dfrac{x}{y}=\dfrac{6}{-6}=\boxed{-1}

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4 years ago
The path of a ball in flight is given by h(x) = -0.23(x – 3.4)^2 + 4.2 where x is
viva [34]

Answer:

B

Step-by-step explanation:

It’s b

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3 years ago
Helpppppppppppp plssss
ExtremeBDS [4]
12 trust me ik it I did it
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