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uysha [10]
3 years ago
10

Simplify completely 10x6y3+20x3y2/5x3y​

Mathematics
1 answer:
Kryger [21]3 years ago
8 0

Answer:

\large\boxed{\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=2x^3y^2+4y}

Step-by-step explanation:

\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=\dfrac{(5x^3y)(2x^3y^2)+(5x^3y)(4y)}{5x^3y}\\\\=\dfrac{5x^3y(2x^3y^2+4y)}{5x^3y}\qquad\text{cancel}\ 5x^3y\\\\=2x^3y^2+4y

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3 years ago
AC is tangent to circle O at point C. What is the length of OC
Sedaia [141]

Let OC is x, so OC=OB=x

{4}^{2}  + x^{2}  =  {(2 + x)}^{2}  \\ 16 +  {x}^{2}  = 4 + 4x +  {x}^{2}  \\ 12 = 4x \\ x = 3

Answer: OC=3 points

6 0
3 years ago
Suppose that 80% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
Gwar [14]

Answer:

P=0.147

Step-by-step explanation:

As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2

We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.

We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) .  To find the required probability 3 mentioned probabilitie have to be summarized.

So P(9/16 )=  C16 9 * P(good brakes)^9*Q(bad brakes)^7

P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02

P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007

P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12

P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147

7 0
3 years ago
A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m
agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

x+20\%x=18

x(1+0.20)=18 (∴20%=\frac{20}{100}=0.20)

x(1.20)=18

x=\frac{18}{1.20}

x=15

Hence, the usual size of the container is 15 ounces.

3 0
3 years ago
What are your recommendations about augmented learning​
Alchen [17]

Answer:

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Augmented learning is closely related to augmented intelligence and intelligence amplification.

Augmented learning is an on-demand learning technique where the environment adapts to the learner. By providing remediation on-demand, learners can gain greater understanding of a topic and stimulate discovery and learning.

Hope this helps you

7 0
2 years ago
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