Answer:
AGCAGCAGCAGC
Explanation:
Messenger RNA (mRNA) is the product of transcription, which is made by synthesizing a complementary strand of the DNA template. The mRNA is a template used to synthesis amino acids during the second process of protein synthesis (translation).
mRNA are read in the ribosomes in a group of three nucleotide sequences called CODON. This codon (triplet nucleotide on mRNA) specifies a particular amino acid. There are 64 possible combinations of codons in the genome for the 20 amino acids. Due to this, the genome/genetic code exhibits a phenomenon called DEGENERACY. Degeneracy is a phenomenon whereby more than one codon specifies a particular amino acid.
The possible CODONS that specify the amino acids given in the question are:
Serine: AGC, AGU, UCA, UCC, UCG, UCU
Glutamine: CAA, CAG
Hence, looking at this codons/nucleotide sequences, we would realize that combining the sequence;
AGCAGCAGCAGC; will produce a serine amino acid sequence, while skipping the first two nucleotides (A and G) and starting from nucleotide C, we will have CAG which codes for Glutamine amino acid repeated three times.
Hence, AGCAGCAGCAGC is the possible mRNA nucleotide sequence that can produce both amino acid sequence.
