Answer:
A. Miguel has the greatest spread.
The range of the two persons can be determined by:
Adam's range = 106 -91
= 15
Miguel's range = 105 -86
= 19
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Adam has the least spread
C. Miguel is inconsistent with the time set for training compared to that of Adam.
The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.
The Pythagorean theorem tells you the square of the hypotenuse is equal to the sum of the squares of the sides.
BC² = AB² + AC²
BC² = 4² +4² = 32
BC = √32 = 4√2
BC = 4*1.41 = 5.64
The length of segment BC is 5.64 m.
Two million forty-six thousand seven hundred and eight.
Divide 560 by 23, 23 goes into 560 24.347 times.
