The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.
<h3>What is the average rate of change?</h3>
The average Rate of Change of the function f(x) can be calculated as;
Interval -3 ≤ x ≤-1
a = -3, b = -1
f(a) = f(-3) = -20
f(b) = f(-1) = 0
Step 2: Find Average
Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.
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Answer:
acute
Step-by-step explanation:
Answer:
16.5 =x
Step-by-step explanation:
Since this is a right triangle, we can us trig functions
tan theta = opp side / adjacent
tan 70 = x /6
Multiply each side by 6
6 tan 70 = x
16.48486452 =x
To the nearest tenth
16.5 =x
To determine if a line is perpendicular to another, you must first determine the slope...
m = y1-y2/x1-x2
m of FK = 3-5/3-6 = -2/-3 = 2/3
m of FJ = 3-2/3-8 = 1/-5
m of FL = 3-0/3-5 = 3/-2
m of KJ = 5-2/6-8 = 3/-2
m of KL = 5-0/6-5 = 5
m of JL = 2-0/ 8-5 = 2/3
In order for two lines to be perpendicular, their slopes must be opposite reciprocals...
FK is perpendicular to FL
FK is perpendicular to KJ
JL is perpendicular to FL
JL is perpendicular to KJ
FJ is perpendicular to KL
f(x) = 5x²
f(10) = 5(10)² = 5(100) = 500
f'(x) = 10x
f'(10) = 10(10) = 100
Now, find the line that passes through (10, 500) and has a slope of 100
y - y₁ = m(x - x₁)
y - 500 = 100(x - 10)
y - 500 = 100x - 1000
y = 100x - 500
