Answer:
L = 2774.4
Explanation:
Using the formula
L = mvr
Where L is angular momentum
m is mass
v is velocity
r is radius
m= 51kg , v=17m/s , r=3.2m
L = 51×17×3.2
L = 2774.4
A ___________ is how strong the push or pull is
2 answers:
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Answer:
Length = 2.32 m
Explanation:
Let the length required be 'L'.
Given:
Resistance of the resistor (R) = 3.7 Ω
Radius of the rod (r) = 1.9 mm = 0.0019 m [1 mm = 0.001 m]
Resistivity of the material of rod (ρ) =
First, let us find the area of the circular rod.
Area is given as:
Now, the resistance of the material is given by the formula:
Express this in terms of 'L'. This gives,
Now, plug in the given values and solve for length 'L'. This gives,
Therefore, the length of the material required to make a resistor of 3.7 Ω is 2.32 m.