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bazaltina [42]
3 years ago
15

PLEASE ANSWER

Mathematics
2 answers:
mr Goodwill [35]3 years ago
6 0

Answer:

nuclear energy

Step-by-step explanation:

zmey [24]3 years ago
6 0
The right answer is convection.
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There are 30 nonfiction books and 34 fiction books in the teachers collection. Which of the following expresses the ratio of fic
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Divide each by 2 and you get 15:16
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3 years ago
Write the numbers 57,000,000,000 and 19,000 in scientific notation. Then show how to divide 57,000,000,000 by 19,000 using prope
LenaWriter [7]

Answer:

the first number is 57 to the ninth power and the second is 19 to the third power, not to sure about the dividing but a quick google search should do the trick

Step-by-step explanation:

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3 years ago
If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro
yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

\Rightarrow f(x) = 2\cos x + e^{2x}

\Rightarrow f'(x) = -2\sin x + 2e^{2x}

And,

\Rightarrow f(2) = 2\cos 2 + e^{4}

\Rightarrow f'(2) = -2\sin 2 + 2e^{4}

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

\Rightarrow y-y_1=m(x-x_1)

\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)

\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})

The value of f(2.1) will be

\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})

\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})

\Rightarrow y=64.5946

According to given function, f(2.1) will be,

\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}

\Rightarrow f(2.1) = 65.6766

\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%

5 0
3 years ago
What two products would you add to find 713​x48
umka21 [38]

9514 1404 393

Answer:

  40·713 and 8·713

Step-by-step explanation:

When this multiplication is carried out "by hand", the usual sum of partial products is ...

  8·713 + 40·713

5 0
3 years ago
Read 2 more answers
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Depends on how much space you have on your device
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