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Lisa [10]
3 years ago
6

What two products would you add to find 713​x48

Mathematics
2 answers:
umka21 [38]3 years ago
5 0

9514 1404 393

Answer:

  40·713 and 8·713

Step-by-step explanation:

When this multiplication is carried out "by hand", the usual sum of partial products is ...

  8·713 + 40·713

Hoochie [10]3 years ago
5 0

Answer:

5704, 28520

Step-by-step explanation:

First find the product of 713 x 48 which is 34224. Next, we find the two products to do so we first add 713 x 8 = 5704.Then,we multiply 713 x 40 which is 28520. This strategie is multiply by the ones then by the tens and add them together to find the your answer.

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SV is a midsegment of △RTU.<br> If TU=y+38 and SV=y–9, what is the value of y?
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Step-by-step explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 = \frac{1}{2} (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

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