What two products would you add to find 713x48

Mathematics

2 answers:

umka21 [38]3 years ago

5 0

9514 1404 393

Answer:

40·713 and 8·713

Step-by-step explanation:

When this multiplication is carried out "by hand", the usual sum of partial products is ...

8·713 + 40·713

Hoochie [10]3 years ago

5 0

Answer:

5704, 28520

Step-by-step explanation:

First find the product of 713 x 48 which is 34224. Next, we find the two products to do so we first add 713 x 8 = 5704.Then,we multiply 713 x 40 which is 28520. This strategie is multiply by the ones then by the tens and add them together to find the your answer.

You might be interested in

12÷3×15(15-6)+3.use order of operations to solve

dlinn [17]

12/3=4
4*15=60
60*(9)=540
540+3=543

4 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2" id="TexFormula1" title="f(x)=x^2-2" alt="f(x)=x^2-2" align="absmiddle"

jek_recluse [69]

Answer:

$\boxed{f(6) = 34}$

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as $(f \circ g)(2)$ , we are replacing the x values in the g(x) function with 2 and simplifying the expression.

$g(2) = 3(2)$

$g(2) = 6$

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

$f(6) = (6)^2-2$