Suppose the number is y >>>>>So y/2 +2y/3 <14
multiply both sides by 6>>>>>>>>>. 6y/2 +6x2y/3 <14x6
3y + 4y < 84
7y <84
y <84/7
y < 12
The probability is 1/12.
There are two outcomes for flipping a coin and 6 for rolling a 6-sided number cube. The sample space is:
(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6)
(T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)
There are 12 total outcomes. Only one has heads and a 2, so the probability is 1/12.
Caleb - c
Kyras - k
k+c=37
c=2k-4
k+(2k-4)=37
3k=41
k=41/3= ~13.67 years old
c=37-k
c=(111-41)/3
c=70/3=~23.33 years old
3x2+8x-10 // the answer is 8x
This situation is represented by the following disjoint inequality:
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- The format of a <u>disjoint inequality</u> is:
- Which is read as: x is more than a or at most b.
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- In this question, we have number m more than
and at most -10, thus, the disjoint inequality that represents this situation is:
A similar problem is given at brainly.com/question/24528399
