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KiRa [710]
3 years ago
13

What is the value of this expression

Mathematics
1 answer:
Finger [1]3 years ago
7 0
8*8*8 = 512. Te negative gets removed.
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When h has the value of 4 calculate 5h-3
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5h - 3 = 17

First, substitute h for 4 and the equation becomes 5(4)-3
Then, use PEMDAS (order of operations) to answer.
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What is 6.4 × 10−8 mi/day in feet per hour? (1 mi = 5280 ft)
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The correct answer is B 1.408 × 10^−5 ft/h <span>
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3 years ago
"Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​
Stella [2.4K]

Answer:

it is not necessary to confirm that the sample data appear to be from a population with a normal ​distribution;

D. Because the sample size of 50 is greater than​ 30, it can be assumed that the sample mean is from a population with a normal distribution

Step-by-step explanation:

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6 0
4 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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