A. A=1/2(6x8)= 24
B=6+15+10=31
SA=2(24)+31(8)=296in.
b.V=1/2(8)(6)(15)=360in.
c. I'm not sure.
Answer:
i) superset (A)
ii) 0.577 (A)
Step-by-step explanation:
i) A subset is a set which has all its elements contained in another set.
For two sets A and B, if each element of set A is an element of set B, then A is a subset of B.
A superset is a set that houses another set. So if set A is a subset of set B, then B is a superset of A.
Proper subset
For a set (A) to be a proper subset of another (B) every element of A would be in B but there exists at least one element in B that is not in A.
An Empty Set (or Null Set) doesn't have aren't any elements in it. It is empty.
Since every element of the superset is in the superset. Therefore, A superset contains all the subset of superset.
ii) Square root of 1/3 = √⅓
= ± √⅓ = +√⅓ or -√⅓
+√⅓ = +(√1/√3) = +(1/√3)
+√⅓ = +(1/1.7321)
+√⅓ = +0.577
Therefore Positive square root of 1/3 is 0.577 (A)
Answer:
I can get you jump started a bit.
Step-by-step explanation:
So Each of those pairs of figures are Similar.
This means they have equal angle measures but different side lengths.
To find it, we have to make a <u>Proportion:</u>
<u>Example: #11</u>
<u />
<u />
So let's solve the first one!
Easy As Pie!
If you need more help, contact me! :)
Hope this Helps!
P.S. Stay Safe!
Answer:
Alex has £44
Pierre has £66
Step-by-step explanation:
P = A + 20
P+ 22 = 2A
solve for A
plug in p
(A + 20) + 22 = 2A
A + 44 = 2A
subtract A from both sides
44 = A
solve for P
plug A in
P = 44 +22
P = 66
Pls give brainlyist
Answer:find the solution to the system of equations below.start by adding the equation
{-2x+2y=-8
{2x+y=5
Step-by-step explanation:The given system of equation are:
1---- y= x -4
2----- y=4 x+2
Equation (1) - Equation (2)
→0= x -4 - (4 x+2)
→0= -3 x -6-----[Adding and subtracting like terms]
Adding 3 x on both sides
→3 x= -6
Dividing by 3 on both sides
→x = -2
→Substituting the value of x in equation 1, we get
y= -2 -4
y =-6
→Solution set =(x,y)=(-2, -6)
Don't used the graph to find the solution.
