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Stolb23 [73]
3 years ago
7

Which pairs of triangles appear to be congruent

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

Photo for Question

Step-by-step explanation:

Luba_88 [7]3 years ago
6 0
You need a picture friend...
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Which of the following is not a method used to prove triangles congruent
RSB [31]
Your answer is D. SSA Postulate because it doesn't exist!
3 0
3 years ago
paul bought a soft and a sandwich for 9.90. what equation may be used to find the price of each item if the sandwich cost 3.5 ti
irina [24]

So, let's say the soft drink equals y and the sandwich equals x.

x + y = 9.9

The sandwich costs 3.5 times as much as the soft drink

x = 3.5y

Therefore, we can replace x with 3.5y since they're the same thing

3.5y + y = 9.9  <-- That's the equation :)


3 0
3 years ago
The area of a square is 484 square inches. How long is each side?
hodyreva [135]

Answer:

\sqrt{484} =22

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Javier is considering two lawn care services. Premier Landscaping charges $15.00 for travel to the job site and $55.00 per hour
Wittaler [7]

Answer:

Time in which both companies charge same cost = 1.5 hour

Step-by-step explanation:

Given:

                                                        Fixed    Variable

Premier Landscaping charges          $15        $55

Ace Landscaping charges                               $65

Find:

Time in which both companies charge same cost:

Computation:

Assume in X time both companies charge same cost:

So,

Premier Landscaping total cost = Ace Landscaping total cost

⇒ $15 + $55(Time taken) = $65 (Time taken)

⇒ $15 = $65 (Time taken) - $55(Time taken)

⇒ $15 = $10 (Time taken)

⇒ Time taken = 1.5 hour

Time in which both companies charge same cost = 1.5 hour

6 0
3 years ago
) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
   5 -1 -6
   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
5 0
3 years ago
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