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nikklg [1K]
3 years ago
10

20 pts + BRAINLIEST

Mathematics
1 answer:
exis [7]3 years ago
7 0
N 4
Part A
a) 7a+2a+3b-------> (7a+2a)+3b-----> 9a+3b
b) 8p+2p-7q-------> (8p+2p)-7q------> 10p-7q
c) 9a²+2a²+5a-----> (9a²+2a²)+5a---> 11a²+5a
d) 5ab+2ab-7a-----> (5ab+2ab)-7a---> 7ab-7a
e) 7+2a-a------> 7+(2a-a)-----> 7+a
f) 2a+3b+5a+2b---> (2a+5a)+(3b+2b)-----> 7a+5b
g) 6p+2q-4p+4q---> (6p-4p)+(2q+4q)----> 2p+6q
h) 9m²+7m²+5m-3m-----> (9m²+7m²)+(5m-3m)------> 16m²+2m
i) 7a²+4a-2a²+7----> (7a²-2a²)+4a+7------> 5a²+4a+7
j) 10p-3q+p-7p-----> (10p+p-7p)-3q------> 4p-3q
k) 3x²+2x-2x²+3x+x²---> (3x²-2x²+x²)+(2x+3x)-------> 2x²+5x

N 5
a) If Julie buys 4 boxes and Michelle buys 7 boxes
in total 
(4+7)*n-----> 7*n
the answer Part 5 a) is 7*n

b) (5kg+3kg)*b---------> 8*b
the answer Part 5 b) is 8*b

c) (3+4+6)*x-------> 13*x
the answer Part 5 c) is 13*x

N 6
a) L+B+L+B------> (L+L)+(B+B)-----> 2*L+2*B-----> 2*(L+B)

b)
1) L+L+L-----> 3*L
2) 5+5+5+5-----> 5*4
3) x+x+y-----> 2*x+y
4) a+b+c+c----> a+b+2*c

N 7
a) s+s+s+s+s+s+s+s------> 8*s
b) t+t+t+t-----> 4*t
c) t+t+t+t+t+t----> 6*t
d) t+t+t+s+s----> 3*t+2*s
e) t+t+t+s+s+s----> 3*t+3*s
f) 12*t+6*s
g) 10 squares+12 triangles-----> 10*s+12*t
h) n squares+m triangles-----> n*s+m*t



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In a test of the effectiveness of garlic for lowering​ cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve
xz_007 [3.2K]

Answer:

With garlic​ treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or paired samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired <em>t</em>-test is used to determine the effectiveness of garlic for lowering​ cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: With garlic​ treatment, the mean change in LDL cholesterol is not greater than 0, i.e. <em>d</em> ≤ 0.

<em>Hₐ</em>: With garlic​ treatment, the mean change in LDL cholesterol is greater than 0, i.e. <em>d</em> > 0.

The information provided is:

\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01

Compute the test statistic value as follows:

t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22

The test statistic value is 0.22.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value of the test as follows:

p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132

*Use a <em>t</em>-table.

The <em>p</em>-value of the test is 0.4132.

<em>p-</em>value= 0.4132 > <em>α</em> = 0.01

The null hypothesis was failed to be rejected.

Thus, it can be concluded that with garlic​ treatment, the mean change in LDL cholesterol is not greater than 0.

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What is the mean of the values in the dot plot?<br><br><br><br> Enter your answer in the box.
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Answer:

The mean is 19.5

Step-by-step explanation:

You have to add all of the numbers up then divide by how many numbers there are.

Ex: 5, 5, 6, 7

add them up and you get 23

Divide 23 by how many numbers you have, which in this case, is 4

The answer to this example would be 5.75

4 0
2 years ago
If the radius of a circle is 3.5 what is the area?
Gala2k [10]

Answer:

A= 12.25π or A≈ 38.48

Step-by-step explanation:

The area formula for a circle is A= πr².

A= πr²

A= π(3.5)²

A= 12.25π or A≈ 38.48

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The formula for the volume sphere is V=4/3pie r^3 what is the formula solved for r?
oksian1 [2.3K]

Answer:

r = \sqrt[3]{\frac{3V}{4 \pi}}

Step-by-step explanation:

From the formula of volume of a sphere we have to isolate "r" on one side of the equation i.e. we have to make "r" the subject of the equation.

V=\frac{4}{3} \pi r^{3}\\\\ \text{Multiplying both sides by 3/4 we get}\\\\\frac{3V}{4} = \pi r^{3}\\\\ \text{Dividing both sides by } \pi \\\\ \frac{3V}{4 \pi} = r^{3}\\\\\text{Takeing cube root of both sides}\\\\\sqrt[3]{\frac{3V}{4 \pi}} = r

Therefore:

r = \sqrt[3]{\frac{3V}{4 \pi}}

3 0
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Dvinal [7]
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basically
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