Let the three consecutive integers be x , x+1 ,x+2
Given, sum of three consecutive integers = -126
x +x+1+ x+2 = -126
3x +3 = -126
3x = -126 -3
3x = -129
x = -129/3
x = - 43
x +1 = -42
x +2 = -41
Answer:
386- Adults 761-students
Step-by-step explanation:
X= 6
Y= 0
Z= -2
CHECK
3x + y -2z =22
3(6) + 0 -2(-2) =22
18 + 0 +4= 22
22=22
x+5y+z =4
6 +5(0)+ -2 =4
6 + 0 +-2 = 4
4=4
x+3z=0
6 + 3(-2) =0
6 -6 = 0
0=0
Answer:
False
Step-by-step explanation:
False because you plug in 2 for d and makes the equation 81 + 2x2 > 90 then it`s just simple math 2x2 is 4 making it 81 + 4 > 90 and the answer is 85 > 90 which is false
OK, so for this equation, your goal is to get the d, and ONLY the d, on one side of the equation. So, to start out, you need to multiply the entire equation, meaning both sides, by 8 because we are trying to get rid of those pesky fractions.
8(1/8(3d-2)=1/4(d+5))
The equation then turns into this because the 8 and 4 cancelled out with the 8.
1(3d-2)=2(d+5)
Now, we need to distribute the left over numbers into the parenthesis.
3d-2=2d+10
And finally, we need to get the d's on one side, and the numbers on the other, so we subtract 2d from both sides and add the 2 to both sides. They then cancel out to make
d=12
Hope it helps! :)
