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beks73 [17]
3 years ago
9

Round the nearest ten in 84,097

Mathematics
2 answers:
julia-pushkina [17]3 years ago
4 0
I'm so happy to help, the answer would be 84,000
uranmaximum [27]3 years ago
3 0
84,100 sidnkooollooooooo
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Find the first , fourth , and eighth terms of the sequence A(n) = -3 •2 ^x - 1
Usimov [2.4K]

Answer:

A(1) = -7

A(4) = -48

A(8) = -769

Step-by-step explanation:

A(n) = -3.2 ^n - 1.....(1)\\\\Plug \: n= 1\: in \: (1)\\A(1) = -3.2 ^1 - 1 =-3.2-1= -6 -1  \\\huge\red{\boxed{A(1) = -7}}\\\\Plug \: n= 4\: in \: (1)\\A(4) = -3.2 ^4 - 1 =-3.16-1= -48 -1  \\\huge\purple{\boxed{A(4) = -49}}\\\\Plug \: n= 8\: in \: (1)\\A(8) = -3.2 ^8 - 1 =-3.256-1= -768 -1 \\\huge\orange{\boxed{A(8) = -769}}

5 0
4 years ago
Scratchpad
olga nikolaevna [1]

Answer:

50 % probability that the hat is blue.

Step-by-step explanation:

3 blue and 3 black = 6 total tickets

3/6 chance of blue and 3/6 change of it being black

3/6 = 1/2 = 0.5 = 50%

5 0
3 years ago
-11/16 what is that lol i’m so lost
Anvisha [2.4K]

-11/16 = -0.6875

What part are you lost on, do you want me to teach you how to divide them?

7 0
3 years ago
Read 2 more answers
James pays $120.00 for golf clubs that are on sale for 20% off at Golf Pros.At Nine Iron, the same clubs cost$8.00 less than the
Oxana [17]

Answer:

17b

Step-by-step explanation:

8980

80987

78987=

6 0
4 years ago
Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
4 years ago
Read 2 more answers
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