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sattari [20]
3 years ago
9

Three points are collinear. never sometimes always

Mathematics
2 answers:
Aloiza [94]3 years ago
4 0

Answer: sometimes

Step-by-step explanation: Three points are <em>sometimes</em> collinear.

In the diagram shown, points B, G, and A are collinear

because these points all lie on the same line.

However, let's look at points A, B, and D.

Since points A, B, and D do not all lie

on the same line, they aren't collinear.

So we know that three points can sometimes be collinear.

adoni [48]3 years ago
3 0
I’m gonna say sometimes
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How to solve this equation?
Novay_Z [31]

Answer:

x = √(28), or x = 5.292

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First you distribute the square to the values inside of the parentheses. so it ends up looking like this

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6 0
3 years ago
The system of equations is given:
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Answer:

x=-1/85; y=-283/85; z=2/17

Step-by-step explanation:

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\left[\begin{array}{ccc}2&-4&6\\9&-3&1\\5&0&9\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}14\\10\\1\end{array}\right]

To begin the calculations, we write the system in augmented matrix form and use the Gaussian elimination:

\left[\begin{array}{ccccc}2&-4&6&|&14\\9&-3&1&|&10\\5&0&9&|&1\end{array}\right]

By applying the Gaussian elimination, the final matrix is the following:

\left[\begin{array}{ccccc}1&0&0&|&-1/85\\0&1&0&|&-283/85\\0&0&1&|&2/17\end{array}\right]

In order to verify the results, it´s enough to substitute the calculated values in the original equations to see if the equalities are correct. Here you can see the verification for all of the equations:

2(-1/85)-4(-283/85)+6(2/17)=14\\9(-1/85)-3(-283/85)+1(2/17)=10\\5(-1/85)+9(2/17)=1

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