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Ray Of Light [21]
3 years ago
10

Find the perimeter of each figure

Mathematics
1 answer:
barxatty [35]3 years ago
5 0
Each has a perimiter of 15
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Which of the following Roots would be between 8 and 7
azamat

To find which of the following roots is between "8" and "7" we can calculate the root of which numbers result in 8 and 7. To do this we will power them by 2, this is done because power is the oposite operation to the root. Doing this gives us:

\begin{gathered} 8^2=64 \\ 7^2=49 \end{gathered}

So the root of 64 is 8 and the root of 49 is 7. We need to find the number that is between 49 and 64.

From the options the only one that qualifies is 52. The correct option is b.

3 0
1 year ago
What is 9.1 less than a number is less than 4.6 equals?
Brilliant_brown [7]

Answer:

n > 13.7

Step-by-step explanation:

Writing a symbolic statement, we get:

n - 9.1 < 4.6

Multiplying all three terms by 10 removes fractions:

10n - 91 > 46

Adding 91 to both sides isolates the 10n term:

10n > 46 + 91, or   10n > 137

Then n > 137/10, or n > 13.7

4 0
3 years ago
Find the volume of this irregular figure.
Musya8 [376]

Answer:

35

Step-by-step explanation:

Area is multiplication! Volume is adding so just add!

6 0
3 years ago
 what is perpendicular to y= 3x -9 and passes through the point (3,1)
GREYUIT [131]
(3,1) , \ \ y= 3x -9 \\ \\ The \ slope \ is :m _{1} =3 \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1} \cdot m _{2} = -1 \\ \\3\cdot m_{2}=-1 \ \ /:3\\ \\ m_{2}=-\frac{1}{3}

\Now \ your \ equation \ of \ line \ passing \ through \ (3,1) would \ be: \\ \\ y=m_{2}x+b \\ \\1=-\frac{1}{ 3} \cdot3 + b

1=-1+b\\ \\ b=1+1\\ \\b=2 \\ \\ y =- \frac{1}{3}x+2


6 0
3 years ago
HELP DUE IN 5 MINUTES​
Daniel [21]

\huge \mathfrak \blue{Solution \:  - }

The formula for area of triangle is -

\frac{1}{2}   \times base \times height

________________________________

So, the area of first triangle =

\frac{1}{2}  \times base \:  \times height

\frac{1}{2}  \times 4  \times 3

=  \pink{6  \: units}

________________________________

Area of second triangle =

\frac{1}{2 }  \times base \times height

\frac{1}{2}  \times 4 \times 6

=  \pink {12 \:  units}

________________________________

Area of second triangle - Area of first triangle

= 12 - 6

= 6

\sf \underline\purple{The \: area \: increases \: by \: 6 \: square \: units.}

3 0
3 years ago
Read 2 more answers
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