A triangle has side lengths of (8d – 3) centimeters, (60 + 2) centimeters, and

The assets division should contain what accounts

fredd [130]

98610100Using your completed Chart of Accounts, choose the one correct answer.1. The assets division should contain what accounts?A. 11 P.Woodsley, Capital12 Equipment—Store13 Equipment—Office14 Cash15 Accounts Payable—Taylor InvestmentsB. 11 Accounts Payable—Bellhaven Bank12 Equipment—Store13 Equipment—Office14 P.Woodsley, Capital15 CashC. 11 Cash12 Equipment—Store13 Equipment—Office14 Prepaid Insurance15 Accounts Payable—Taylor InvestmentsD. 11 Cash12 Prepaid Insurance13 Equipment—Store14 Equipment—Office15 Supplies2. The liabilities division should contain what accounts?A. 21 Accounts Payable—Bellhaven Bank22 P.Woodsley—CapitalB. 21 Accounts Payable—Bellhaven Bank22 Accounts Payable—Taylor InvestmentsC. 2122D. 21 Accounts Payable—Bellhaven Bank22 Merchant’s Bank3. The owner’s equity division should contain what account(s)?A. 31 P.Woodsley—Capital

4 0

3 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

Write an equation of the line passing through point p that is parallel to the given line.

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

y=-3x+13

y = mx + b, where m is the slope and b is the y-intercept.

A line parallel to this line will have the same slope, -3. We can start by writing:

y = -3x + b

No matter what is chosen for the value of b, this line will be parallel. We do want the line to go through point (6,10), however. The way that can be done is to find a value of b that would shift the line to go through (6,10).

Find b by entering the point (6,10) into the equation, and then solve for b:

y = -3x + b

10 = -3(6) + b

10 = -18 + b

b = 28

The line becomes y = 3x + 28

See the attachment.

8 0

2 years ago

What is the midpoint of 0 1000

ruslelena [56]

I think it might be 500

hope this helped =3

5 0

2 years ago

Read 2 more answers

Solve please i’ll give brainliest

valina [46]

Answer:

3 is 60°, as well as 5 and 7 and the rest are 120°

Step-by-step explanation:

6 0

3 years ago