This can solved using the cosine law which is:
c² = a² + b² - 2ab cos θ
Using the values given from the problem
6² = b² + b² - 2bb cos 112.62
And solving for b
36 = 2b² - 2b² cos 112.62
b = 3.6
The answer is the 3rd option.
The shape of the cross-section formed is a triangle, when a cone is cut in such a way that the cross-section is perpendicular to the base and it passes through the vertex.
Answer:
(a) Circle Q is 9.4 units to the center of circle P
(b) Circle Q has a smaller radius
Step-by-step explanation:
Given


Solving (a): The distance between both
The equation of a circle is:

Where


P and Q can be rewritten as:


So, for P:


For Q:


The distance between them is:

Where:
--- 
--- 
So:





Solving (b): The radius;
In (a), we have:
--- circle P
--- circle Q
By comparison

<em>Hence, circle Q has a smaller radius</em>