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A.) P(t) = P0exp(kt)
P(20/60) = 40 exp(20k/60)
80 = 40 exp(k/3)
exp(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = exp(8k) = exp(8(3ln(2)) = exp(24ln(2)) = exp(16.6355) = 16777216 cells / hour
e.) P(t) = 40(2)^3t; t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
Answer:
y = 1/3
Step-by-step explanation:

(-11.2)+10.1 = -1.1
(-11.2) +10.1 and 11.2+ (-10.1) are related because the negative signs are switch so both equations have the same answer.
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Answer:
see attached
Step-by-step explanation:
I like to use a spreadsheet for repetitive calculations. The distances are computed from the distance formula:
d = √((x2 -x1)^2 +(y2 -y1)^2)
The results are shown in the second attachment. The drawing in the first attachment has the lengths rounded to the nearest tenth.