Answer:
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The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²
Answer:
D) 12
Step-by-step explanation:
3x+x=2x+24
4x=2x+24
4x-2x=24
2x=24
x=24/2
x=12
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The capacity of an Airliner is k = 300 passengers
The sample size n = 320 passengers
The probability the a randomly selected passenger shows up on to the airport

Generally the mean is mathematically represented as
=>
=>
Generally the standard deviation is

=> 
=> 
Applying Normal approximation of binomial distribution
Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

Here 
=>
Now applying continuity correction we have
=> ![P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20%5Cfrac%7B%5B300.5%5D%20-%20307.2%7D%7B3.50%7D%20%29)
=> 
From the z-table

So
