Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
No circumference of a circle is very easy to me
Treat it just like and equation at first. Multiply the 10 on both sides to get rid of it, leaving you with 50 
x. Then on the number line, since there is a line under it, you would make a filled in circle and an arrow pointing towards 51 and beyond
Answer:
y^ ⁻⁹/⁴ * z^⁽⁻³⁾
Step-by-step explanation:
(Y^3 z^4)^(-3/4) = (y^3)^(-3/4) * (z^4)^(-3/4)
= y^3* ⁽⁻³/⁴⁾ * z^4 *⁽⁻³/⁴⁾
=y^ ⁻⁹/⁴ * z^⁽⁻³⁾
