Ask question

Ask question

All categories

3 years ago

9

Proszę o pomoc ! Pilne !

1 answer:

pav-90 [236]3 years ago

7 0

H because it adds up to 46

You might be interested in

F(h) = -2(h - 4)2 + 22.

Ivenika [448]

Here’s what I found that can help you step by step

5 0

2 years ago

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago

Evaluate the expression using order of operations. (24+2) ÷ 2

Reptile [31]

Answer:

The answer is 13

Step-by-step explanation:

24+2=26

26÷2=13

7 0

2 years ago

A bag contains 17 cards numbered 1 through 17 . A card is randomly chosen from the bag. What is the probability that the card ha

Pachacha [2.7K]

Answer: 8/17

Explanation:
2, 4, 6, 8, 10, 12, 14, 16 are all the possible even numbers from 1 through 17.

6 0

3 years ago

Six students are working to simplify the expression shown. Drag each student's answer to a box to show whether it is fully simpl

Sever21 [200]

Answer:

2x -18x +14y -19 = -16x +14y -19 . . . not the same

-2xy -1 . . . not the same

16x +14y -1 . . . not the same

9 -16x +14y -10 = -16x +14y -1 . . . equivalent

-16x +14y -1 . . . equivalent and simplified

2x -18x +14y -1 = -16x +14y -1 . . . equivalent

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers