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2 years ago

9

Alex is making 14 fruits salads for a party. He places 9 cherries in each of his fruits salads. What is the total number of cher

ries Alex uses for his fruits salads?

2 answers:

raketka [301]2 years ago

7 0

The number of cherries used in 14 fruit salads will be 126.

saul85 [17]2 years ago

5 0

Alex uses 126 cherries for his fruit salads.

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A certain corporation listed their sales in 100s as 1,700. What was their actual volume in thousands?

svp [43]

Answer: 170

Step-by-step explanation:

Based on the problem, you know that this corporation listed their sales in 100s as 1,700. This means that, to calculate their actual volume in thousands, you need to multiply 1,700 by 100 and divide the product by 1,000.

Let be "x" their actual volume in thousands.

Therefore, applying the corresponding procedure, you get that the value of "x" is the following:

$x=\frac{(1,700)(100)}{(1,000)}\\\\x=\frac{170,000}{1,000}\\\\x=170$

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3 years ago

✓<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B19%20%2B%20%20%5Csqrt%7B30%20%2B%20%20%5Csqrt%7B32%20%2B%20x%20%20%7D%20%7D%

Setler79 [48]

We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields

$19+\sqrt{30+\sqrt{32+x}}=25$

Move the 19 to the right hand side:

$\sqrt{30+\sqrt{32+x}}=6$

And square again:

$30+\sqrt{32+x}=36 \iff \sqrt{32+x}=6$

Square one last time:

$32+x=36 \iff x=36-32=4$

Let's check the solutions: all these squaring might have created external solutions:

$\sqrt{19+\sqrt{30+\sqrt{32+4}}}=\sqrt{19+\sqrt{30+6}}=\sqrt{19+6}=\sqrt{25}=5$

So, $x=4$ is a feasible solution.

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DerKrebs [107]

Answer:

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Step-by-step explanation:

7 goes into 21 3 times, so the first digit of the quotient is 3. There's no remainder. Bringing down the second "1," we find this indivisible by 7, and so bring down the 6.Thus, Remember that 7 goes into 14 2 times. Thus, a good estimate would be 302.

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Answer:

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Step-by-step explanation:

Since you're finding the angle, you use the inverse of sin, cos, and tan.

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