15x12=180
180$ simple unless u have a different way to do it
Answer:
b. t = 10.5 seconds.
Step-by-step explanation:
l = 0.81t^2
90 = 0.81t^2
t^2 = 90 / 0.81
t^2 = 111
t = 10.5 seconds.
You will need to set up and solve 2 equations:
A) 3 Vans + 10 Buses = 379
B) 14Vans + 13 Buses = 624
Multiply equation A by -14
A) -42 Vans -140 Buses = -5,306 then Multiply equation B by 3
B) 42 Vans + 39 Buses = 1,872
Adding BOTH equations
-101 Buses = -3,434
Each Bus holds 34 Students
Putting this into equation A
A) 3 Vans + 10 Buses = 379
A) 3 Vans + 10 * 34 = 379
A) 3 Vans +340 = 379
A) 3 Vans = 39
Each van = 13 students
19/38 and 15/18
Explanation:
19/38 can be reduced as there is a factor other than 1 that can divide without a remainder. Factor is 19
It can still be reduced because 19*2 = 38
19/38 = 1/2
10/19 cannot be reduced as there is no factor other than one to divide without a remainder
21/34 cannot be reduced as there is no factor other than one to divide without a remainder
15/18 can be reduced as there is a factor other than 1 that can divide without a remainder.
The factor is 3
15/18 = 5/6
Fraction that has not been reduced to simplest form are 19/38 and 15/18
Answer:
The completed proof is presented as follows;
The two column proof is presented as follows;
Statements 
Reason
1. 
║ 
, J is the midpoint of 
1. Given
2. ∠IHJ ≅ ∠JLK 2. Alternate angles are congruent
3. ∠IJH ≅ ∠KJL 3. Vertically opposite angles
4. 
≅ 
4. Definition of midpoint
5. ΔHIJ ≅ ΔLKJ 5. By ASA rule of congruency
Step-by-step explanation:
Alternate angles formed by the crossing of the two parallel lines and , by the transversal are equal
Vertically opposite angles formed by the crossing of two straight lines 
and are always equal
A midpoint divides a line into two equal halves
Angle-Side-Angle, ASA rule of congruency states that two triangles ΔHIJ and ΔLKJ, that have two congruent angles, ∠IHJ in ΔHIJ ≅ ∠JLK in ΔLKJ and ∠IJH in ΔHIJ ≅ ∠KJL in ΔLKJ, and that the included sides between the two congruent angles is also congruent ≅ , then the two triangles are congruent, ΔHIJ ≅ ΔLKJ.
