1) You must add 4 to each side to complete the square.
2) You must add 16 to each side to complete the square.
3) You must add 27 to each side to complete the square.
Explanation:
1) x²-4x=0
To find the number that we add to both sides, we look at b, the cofficient of x. It is -4. We divide it by 2 and square it; -4/2 = -2; (-2)² = 4. This is the value that we add to both sides.
2) x²-8x=6
-8/2 = -4; (-4)²=16
We add 16 to each side to complete the square.
3) 3x²+18x=24
First we can factor a 3 out of the left side:
3(x²+6x) = 24
Our b value is now 6. 6/2 = 3; 3²=9. The 9 would, however, go in the parentheses, so it would be multiplied by 3, which makes 27; this means we would add 27 to both sides.
Answer:
12cm^2
Step-by-step explanation:
1/2 x diagonal x diagonal
Y= -9x
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8
hope this helps
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<span>34a^2 b = 2a^2b(17)
24a^5 b^2 = 2ab(12a^3b)
answer
</span>greatest common factor of these monomials = 2ab
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>