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Radda [10]
3 years ago
5

What is the concentration of a solution in which 0.99 g of KOH are dissolved in 500 mL?

Chemistry
1 answer:
aliina [53]3 years ago
5 0

Answer:

.00352mol/L

Explanation:

molarity (concentration) = number of moles / volume of solvent (in L)

M = .99g / 56.108‬g/mol / .5L

M = .0176mol / .5L

M = .00352mol/L

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First we<u> convert 5.25x10³² atoms to moles</u>, using <em>Avogadro's number</em>:

5.25x10³² atoms ÷ 6.023x10²³ atoms/mol = 88.72x10⁸ mol

Then we<u> convert K moles to grams</u>, using its <em>molar mass</em>:

88.72x10⁸ mol * 39 g/mol = 3.40x10¹⁰ g

So 5.25x10³² atoms of K would weigh 3.40x10¹⁰ grams.

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