Answer:
1.18 moles of CS₂ are produced by the reaction.
Explanation:
We present the reaction:
5C + 2SO₂ → CS₂ + 4CO
5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.
As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:
70.8 g / 12 g/mol = 5.9 moles
Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂
Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles
Answer:
Water acutually has a higher boiling point because CO2 will turn into a gas form at a certain temp ( -78 C), so CO2 wouldn't really boil very long.
Hope this helps:)
<u>Answer:</u> The molar mass of the sample is 120.6 g/mol
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:
Or,
where,
= depression in freezing point = 0.42°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point elevation constant = 5.065°C/m
= Given mass of solute (sample) = 0.500 g
= Molar mass of solute (sample) = ? g/mol
= Mass of solvent (benzene) = 50.0 g
Putting values in above equation, we get:
Hence, the molar mass of the sample is 120.6 g/mol
All u do is divide the mass by the volume so 85.4/7 which is 12.2
