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Answer:
After 6sec 5 atoms will be left.
Explanation:
Given data:
Total atoms of Highlinium = 40
Half life = 2 sec
Atoms left after 6sec = ?
Solution:
First of all we will calculate the number of half lives passes during 6sec.
Number of half lives = Time elapsed/ half life
Number of half lives = 6 sec / 2sec
Number of half lives = 3
Now we will calculate the number of atoms left
At time zero = 40 atoms
At 1st half life = 40 atoms/2 = 20 atoms
At 2nd half life = 20 atoms/2 = 10 atoms
At 3rd half life = 10 atoms / 2 = 5 atoms
Thus, after 6sec 5 atoms will be left.
Explanation:
Ammonium lauryl sulfate (ALS) is the common name for ammonium dodecyl sulfate (CH3(CH2)10CH2OSO3NH4). The anion consists of a nonpolar hydrocarbon chain and a polar sulfate end group. The combination of nonpolar and polar groups confers surfactant properties to the anion: it facilitates the dissolution of both polar and non-polar materials. ALS is classified as a sulfate ester. It is found primarily in shampoos and body wash as a foaming agent. Lauryl sulfates are very high-foam surfactants that disrupt the surface tension of water in part by forming micelles at the surface-air interface.
