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luda_lava [24]
3 years ago
7

Suppose 8 out of 20 students are absent from school less than five days a year. Predict how many students would be absent from s

chool less than five days a year out of 40,000 students
Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
40,000 x 8 divided by 20 = 16,000 absent students.
goldfiish [28.3K]3 years ago
7 0
16,000 students is what i got as my answer.
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This for math. Rewriting Fractions <br> How do you decide which number to use in the Giant One?
ASHA 777 [7]

Answer:

factor of hundred is

100 - 1, 2,4,5,10,100

4 0
3 years ago
The point slope form of the equaton of the line that passes through (-9, -2) and (1, 3) is y-3=1/2(x-1). What is the slope-inter
igomit [66]

Answer: y=1/2x+5/2

Step-by-step explanation:

y-3=1/2 (x-1)

y-3(-3)=1/2x-1/2(+3)

y=1/2x-1/2+6/2

y=1/2x+5/2

hope this helped!!

3 0
3 years ago
Simplify 6.92 to the exponent of 1000
melisa1 [442]

Answer:

Whatever is raised to the power of 0 is 1

SO the answer is 1

4 0
3 years ago
Rewrite each statement using the appropriate mathematical language 1. There exists a number b belonging to the set B 2. Even num
Shtirlitz [24]

Answer:

1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻

Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

N ⊂ Z ⊂ Q ⊂ R .

4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write

J ≤ J⁻¹ : J ∈ Z⁻

4 0
3 years ago
In the system of equations below, which variable would it be easiest to solve for? x + 4 y = 14. 3 x + 2 y = 12 The easiest to s
Murljashka [212]

Answer:

<h2>The easiest to solve for is x in the first equation</h2>

Step-by-step explanation:

Given the system of equation, x + 4 y = 14. and 3 x + 2 y = 12, to solve for x, we can use the elimination method of solving simultaneous equation. We need to get y first.

x + 4 y = 14............ 1 * 3

3 x + 2 y = 12 ............ 2  * 1

Lets eliminate x first. Multiply equation 1 by 3 and subtract from equation 2.

3x + 12 y = 42.

3 x + 2 y = 12

Taking the diffrence;

12-2y =42 - 12

10y = 30

y = 3

From equation 1, x = 14-4y

x = 14-4(3)

x = 14-12

x = 2

It can be seen that the easiest way to get the value of x is by using the first equation and we are able to do the substitute easily <u>because the variable x has no coefficient in equation 1 compare to equation 2 </u>as such it will be easier to make the substitute for x in the first equation.

5 0
4 years ago
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