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Elden [556K]
3 years ago
13

Examine the following sequence 1, 4, 9, 16, 25…. Why is 36 the next number in the sequence? Because the pattern is: a. Add the n

ext even number c. Cube the number of the term, n b. Square the number of the term, n d. Add 2 + the number of the term, n
Mathematics
1 answer:
olga2289 [7]3 years ago
7 0
Square roots the square root of 1 is one square root of 2 is 4 square root of 3 is 9 and ect.
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If a+b+c =0 show that a³+b³+c³= 3abc
slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0
3 years ago
Write the fraction<br> in simplest form.<br> 42/49
lozanna [386]

Answer:

6/7 is the ans

42 & 49 is divided by 7

4 0
3 years ago
Identify an equation in point-slope form for the line perpendicular to y =3/4x -4 that passes through (-1, 7).
PilotLPTM [1.2K]

Answer:

y - 7 = -4/3(x + 1)

Step-by-step explanation:

<u>Given</u>

  • y =3/4x -4
  • (-1, 7)

<u>Convert to point slope form</u>

y - y1 = m(x - x1)

m: represents what the slope is

y - 7 = -4/3(x + 1)

<u>Distribute -4/3</u>

-4/3 * x = -4/3x

-4/3 * 1 = -4/3

y - 7 = -4/3x - 4/3

<u>Add seven in both sides</u>

21/3 -4/3 = 17/3

y = -4/3x + 17/2

<u>Answer</u>

linear equation: y = -4/3x + 17/2

point-slope form: y - 7 = -4/3(x + 1)

3 0
3 years ago
Which of these numbers are perfect squares or perfect cubes? Select the THREE answers that apply. 8 16 32/ 64 128 6 Omestian 12​
Murljashka [212]

Answer:

  8, 16, 64

Step-by-step explanation:

  8 = 2^3 . . . a perfect cube

  16 = 4^2 . . . a perfect square

  32 = 2^5 . . . neither a cube nor a square

  64 = 2^6 = 4^3 = 8^2 . . . both a perfect cube and a perfect square

  128 = 2^7 . . . neither a cube nor a square

8 0
3 years ago
Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of e
emmainna [20.7K]

This question is incomplete, the complete question is;

Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of equations in terms of x, y, z, and t.) The line passes through the point (3, 1, 2) and is parallel to the line given by x  = y = z.

Answer:

the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

Step-by-step explanation:

Given that;

line x = y = z and point ( 3, 1, 2 )

the given line can be written as;

[x-0 / 1] = [y-0 / 1] = [z-0 / 1]

if two lines are parallel directional ratios are equal.

so DIRECTIONAL RATIOS  of given line is ( 1, 1, 1 )

therefore required line is;

[x-3 / 1] = [y-1 / 1] = [z-2 / 1] = t

⇒ [x-3 / 1] = t

x = t+3

[y-1 / 1] = t

y = t+1

[z-2 / 1] = t

z = t+2

Therefore the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

8 0
3 years ago
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