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nydimaria [60]
2 years ago
11

What number makes the equation true? Enter the answer in the box. - 5 = 9

Mathematics
1 answer:
leonid [27]2 years ago
8 0

Answer:

14

Step-by-step explanation:

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4-x suare= -16 what is the answer
Snowcat [4.5K]

4-x^2=-16\\\\
x^2=20\\\\
x=\sqrt{20} \vee x=-\sqrt{20}\\\\
x=2\sqrt5 \vee x=-2\sqrt5

7 0
3 years ago
Read 2 more answers
Write log3 6 as a logarithm of base 2.
Sever21 [200]
Use:\\\log_ab=\dfrac{\log_cb}{\log_ca}\ and\ \log_ab+\log_ac=\log_a(bc)\\\\\log_36=\dfrac{\log_26}{\log_23}=\dfrac{\log_2(2\cdot3)}{\log_23}=\dfrac{\log_22+\log_23}{\log_23}\\\\=\dfrac{\log_22}{\log_23}+\dfrac{\log_23}{\log_23}=\boxed{\dfrac{1}{\log_23}+1}\\\\other\ method\\Use:\\\log_ab=\dfrac{1}{\log_ba}\\\\\log_36=\log_3(2\cdot3)=\log_32+\log_33=\log_32+1=\boxed{\dfrac{1}{\log_23}+1}
4 0
3 years ago
A rectangle is such that the length of 2 of each adjacent sides are in the ratio 1:3. A similar rectangle has 1 side of 6cm. Fin
Sliva [168]

Answer:

18 cm ;

2 cm

Step-by-step explanation:

Length of each adjacent side = 1 :3

If 1 side = 6 ; the possible values of the adjacent side ;

That is side 2 ÷

If side 1, which is 6cm is the ratio 1 ; then side 2 = 6cm * 3 = 18 cm

If side 1, which is 6cm is the ratio 3 ; then side 2 = 6cm / 3 = 2 cm

Hence, the two Possible values of the adjacent side = 18 cm or 2 cm

8 0
2 years ago
K/13 = 0.6/0.5 what does that equal
photoshop1234 [79]
\frac{k}{13} = \frac{0.6}{0.5} equals k = 15.6

First,
simplify \frac{0.6}{0.5} to 1.2. Your problem should look like: \frac{k}{13} = 1.2
Second, multiply both sides by 13. Your problem should look like: k = 15.6, which is the answer.
5 0
3 years ago
1.<br> What is the solution?<br> y<br> 3<br> -3-2-1<br> 2 3x<br> O (1,2)<br> O (1,-1)<br> O 1<br> 02
Rama09 [41]

9514 1404 393

Answer:

  (d)  Infinitely Many Solutions

Step-by-step explanation:

Each point of intersection between the lines is a solution. When the lines lie on top of each other, there are infinitely many points of intersection, hence ...

  Infinitely Many Solutions

4 0
3 years ago
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