Question

Please help me out!!!!!

Answer 1

We have three pythagoras:

4² + y² = z²

16² + y² = x²

x² + z² = 20²

Now let's think:

4² + y² = z²

y² = z² - 4²

16² + y² = x²

16² + z² - 4² = x²

x² + z² = 20²

16² + z²- 4² + z² = 20²

2z² = 20² - 16² + 4²

2z² = (2.10)² - (2^4)² + (2²)²

2z² = 2².10² - 2^8 + 2^4

z² = 2.10² - 2^7 + 2^3

z² = 200 - 128 + 8

z² = 208 - 128

z² = 80

z = √80

80 | 2

40 | 2

20 | 2

10 | 2

5 | 5

1

80 = 5.2^4

So

√80 = 4√5

z = 4√5