Use ideal gas law PV=nRT
at STP, pressure is 1atm and temperature is 273K (0 Celsius)
1×1.5L=n × 0.0821 × 273
n is moles and R is ideal gas law constant, always 0.0821
moles= 14.9422(6.02×10^23 molecules)=9.0×10^24 molecules
CH4 + 2O2 --> CO2 + 2H2O
On the reactant side you start with 1 carbon, 4 hydrogen, and 2 oxygen. On the product side you start with 1 carbon, 2 hydrogen, and 3 oxygen. In order to get them equal, you need to put 2 in front of the H2O which equals out the number of Hydrogen on both sides. But Now we must balance the Oxygens. Because of the H2O we now have 4 Oxygens on the product side and only 2 on the reactant. In order to balance this, we put a 2 in front of the O2 giving us 4 hydrogen on both sides, Balancing the equation
Hello, this question is incomplete. The complete question would be:
"Write the balanced chemical equation for the following reaction.
Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water"
Answer:
Fe2O3 + 3 H2 = 2 Fe + 3 H2O
Explanation:
In a chemical reaction, the structure of atoms as chemical elements is unchanged. Atoms in one element do not become atoms in another element. There is also no loss or creation of new atoms. The number of atoms of the reagents must be equal to the number of atoms of the products. When this happens, we say that the chemical equation is balanced.
For this reason, we can state that the balanced chemical reaction where solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water would be:
<em>Fe2O3 + 3 H2 = 2 Fe + 3 H2O
</em>
Answer:
C. Between 0 and 1 seconds
Explanation:
Since 0 - 1 seconds the car accelerates to 20mph. The rest each second the car accelerates 5mph.
