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Semenov [28]
3 years ago
11

In the following reaction, when a surplus of hydrazine (N2H4) reacts with 20 liters of hydrogen peroxide (H2O2), how many liters

of nitrogen gas will be released, given that both gases are at STP?
N2H4 + 2H2O2 →N2 + 4H2O


10 liters



0.1 liters



40 liters



20 liters
Chemistry
2 answers:
Ghella [55]3 years ago
5 0
The answer is 10 liters.
Kaylis [27]3 years ago
5 0

The correct answer is

10

:)

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Answer:

N₂ = 0.7515atm

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Explanation:

For the reaction:

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Where Kp is defined as:

Kp = \frac{P_{NO}^2}{P_{N_2}P_{O_2}}}

Pressures in equilibrium are:

N₂ = 0.790atm - X

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NO = 2X

Replacing in Kp:

0.0460 = [2X]² / [0.790atm - X] [0.210atm - X]

0.0460 = 4X² / 0.1659 - X + X²

0.0460X² - 0.0460X + 7.6314x10⁻³ = 4X²

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Solving for X:

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X = <em>0.0385 atm</em> → Right answer.

Replacing for pressures in equilibrium:

N₂ = 0.790atm - X = <em>0.7515atm</em>

O₂ = 0.210atm - X = <em>0.1715atm</em>

NO = 2X = <em>0.0770atm</em>

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