Answer:
no this is for actual question for students not for memes bro
Answer:I don't know the exact problem but I'll just give you the formulas on how to find volume, circumference radious, and yada
Step-by-step explanation: to find volume.. you need to multiply pi times the radius to the power of 2.. to find the radius you need to divide the height and pi by the volume.. to find the cylinder circumference you need to multiply the radius by 2 the multiply the radius by pi which is 3.14
Answer:
V = 125 cm³
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
Volume of a Cube Formula: V = a³
- <em>a</em> is any side length
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
<em>a</em> = 5 cm
<u>Step 2: Find Volume</u>
- Substitute in variables [Volume of a Cube Formula]: V = (5 cm)³
- Evaluate exponents: V = 125 cm³
5).
and
6).
The volume of a sphere is
(4/3) (pi) (radius)³ .
In #5, the 'pi' is already there next to the answer window.
You just have to come up with the (4/3)(radius³).
Remember that the radius = 1/2 of the diameter.
7). The volume of a cylinder is
(pi) (radius²) (height) .
Divide the juice in the container by the volume of one can,
to get the number of cans he can fill.
8). The volume of a cone is
(1/3) (pi) (radius of the round bottom)² (height) .
He starts with a small cone, he then adds clay to it to make it higher.
The question is: How much clay does he ADD to the short one,
to make the bigger one ?
Use the formula to find the volume of the short one.
Use the formula again to find the volume of the bigger one.
Then SUBTRACT the smaller volume from the bigger volume.
THAT's how much clay he has to ADD.
Notice that the new built-up cone has the same radius
but more height than the first cone.
_______________________________________
Don't worry if you don't understand this.
The answer will be this number:
(1/3) (pi) (radius²) (height of the big one minus height of the small one).
